Sunday, July 30, 2023

figure it out

More racist math fo' yo' ass!

This is another easy one. My answer will be in the comments.



1 comment:

  1. We're given three overlapping rectangles that create five "sub-rectangles." The yellow sub-rectangle has an area of 96 square centimeters; the light-blue rectangle has an area of 36; the light-green rectangle has an area of 48; the mauve rectangle has an area of 80. The length x is the sum of the "north" side of the yellow rectangle plus the "north" side of the light-blue rectangle. We're given the length of the sum of the "south" sides of the light-green and mauve rectangles: 10 centimeters.

    First, note that we can solve for the length of the "west" side of the green rectangle (call it "a") easily enough: we know the area of light-green + mauve = 48 + 80, so we automatically know

    10a = 128

    Therefore, a = 12.8 cm.

    Knowing that, we can solve for the "north" side of the light-green rectangle (b):

    12.8b = 48

    b = 3.75

    This means we can solve for the "east" side of the light-blue rectangle (d, because I chose "c" for the "north" side of the mauve rectangle but never had to use that):

    3.75d = 36

    d = 9.6

    We can now solve for e, the "north" side of the yellow rectangle:

    9.6e = 96

    e = 10

    The length x is basically the sum of e + b, so

    10 + 3.75 = 13.75

    x = 13.75

    QED.

    ReplyDelete

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