Not much difference between this and a GRE problem, in my opinion. I encountered this one (well, a problem similar to this one) while helping a student review errors he'd made on a practice SAT.
Have at it.
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Monday, October 03, 2011
SAT problem for you
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2 comments:
Area of Sector ABC = 108π
If I'm right, send me a quick email to confirm. Here's how I attacked it.
30degrees for angle ACB = 1/12 of circle.
6π = 1/12 of circumference = 1/12 * 2π * r. So, r = 36.
Area of ABC = 1/12 of area of circle = 1/12 * π * (36)^2 = 108π
You got it!
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